An object is moving with a velocity of 5m^-1. At what height must a similar body be situated to have a potential energy equal in value with kinetic energy of the moving body?

Osheke

1 year ago

i don't know but i think i will kick against this,
because before a similar body will have potential energy equal it's Kinectic energy, the body must be situated at the center, meaning half the distance, so the correct formula to use is;

H = v²/4g

The formula you use is for maximum height, and at the maximum height;
the energy present there is potential only.
it is only at the center where K.E = P.E


just like this question;


If a body mass 5kg is thrown vertically upwards with velocity u,at what height will the potential energy equal to the kinetic energy?

A. h =(u)2/g
B. h = (u)2/4g
C. h = (2u)2/g
D. h = (u)2/2g

Standing to be corrected tho

obig6479

1 year ago

To solve this problem, we need to equate the kinetic energy (KE) of the moving object with the potential energy (PE) of the stationary object.

Kinetic Energy (KE) = 0.5 × m × v^2

where m is the mass of the object and v is its velocity.

Potential Energy (PE) = m × g × h

where g is the acceleration due to gravity (approximately 10 m/s^2) and h is the height.

Since the objects are similar, we can assume their masses are equal. Therefore, we can set up the equation:

0.5 × m × v^2 = m × g × h

Now, plug in the values:

0.5 × m × (5 m/s)^2 = m × 10 m/s^2 × h

Simplify the equation:

0.5 × 25 = 10 × h

h = 1.25 m

However, this answer is not among the options. Let's try to find the closest answer:

The closest answer is C. 1.3m.

So, the correct answer is C. 1.3m.