An object of mass 20kg is released from a height of 10m above the ground level. The kinetic energy of the object just before it hits the ground is

adejare98

9 years ago

Here is an explanation. K.E=1/2MV^2. but there is no V in the question nd we must find it. Therefore. V^2=U^2+2gh.

V^2=O^2+2*10*10.

V^2=200.

Back to K.E=1/2MV^2.

K.E=20*200/2

K.E=4000/2

K.E=2000J.

Thanks!!

Dovella

9 years ago

K.E=P.E=mgh

obedvictor

9 years ago

Lolz,u tried helping them out,may they've forgotten how they were taught. K.E=P.E

K.E=mgh.

Domshak paul

9 years ago

K.E=P.E,=mgh

where m=mass, g=gravity, h=height

gozie victor

11 years ago

These is a wrong formula,the formula for kinetic energy is 1/2MVsquare

ADEBAYOSEGUN

10 years ago

The answer should be 1000J (½MV²)

Hrlar

3 years ago

answer not there
right formula is 1/2mvsquare

bonge

8 years ago

Here is the correct explanation:

K.e=1/2mv^2

=1/2*20*10*10

=1000