A progressive wave has a wavelength of 50cm. calculate the phase difference between two points at a distance of 20cm apart.

JThomson

6 years ago

Phase difference is [2(Pi)x]/Lambda
Lambda is 50
[2×(Pi)×20]/50
= (4/5)Pi

timothy09

12 years ago

the diff. btw them is what we are ask to fimd. soo 50cm/20cm =5/2.

ojosunday

9 years ago

phase difference equals kx where k from the wave equation equals 2#x/lambda ...substitute the values given above 2*20*#/50=40#/50 ans =4#/5 i.e c

shibab

10 years ago

phase difference(@) is equal to 2pi.X/L where x=20cm nd l=wave length= 50. der4 d phase diff. = 2pi *20/50=40pi/50 = 4pi/5. option C.

esther fred

10 years ago

please I need to get the formula used in solving it now please

Damfem

10 years ago

Dat 2ru I got 5/2 here

Damfem

10 years ago

Can sum 1 send me his whatapp no so dat we can revive 2head

DesmondEmmanuel

6 years ago

Pls can the workings be included?

Emmanuel 77

10 years ago

pls more explanation becoz is didn't clear to me