When a resistor of resistance R is connected across a cell, the terminal p.d of the cell is reduced to three quarters of its e.m.f. The internal resistance of the cell is expressed as
a
R/4
b
R/3
c
R/2
d
3R/4
e
3R
Explanation
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Discussions (7)

JThomson
6 years ago
E=IR+Ir
IR=(3/4)E
Ir=(1/4)E
r=[(1/4)E]/I
4Ir=E
E=I(r+R)
4Ir=I(r+R)
4r=r+R
3r=R
r=R/3

joymaxwell
4 years ago
According to the question, V=3/4E
so E=4V/3 but E is also IR + Ir so E = V +Ir
4V/3 = V + Ir
4V = 3V + 3Ir
V = 3Ir
r =V/3I
r=IR/3I
r = R/3



