A ball of mass 0.1kg approaching a tennis player with a velocity of 10ms\(^{-1}\),is hit back in the opposite direction with a velocity of 15ms\(^{-1}\). If the time of impact between the racket and the ball is 0.01s, calculate the magnitude of the force with which the ball is hit

Dave333

4 years ago

My school are absolutely correct,I forget that the ball bounce back in opposite direction,making 10 negative.You have to calm down and read some questions when you about calculating 😄

SammyKush011

5 years ago

M= 0.1kg = 1×10^-1kg u= 10 v = -15(negative due to being directed in the opposite direction)
t= 0.01s = 1×10^-2s
F= [m(v-u)]/t
=10^-1(10-(-15)/10^-2
=25×10^-1 × 10^2
= 25×10
=250N

Afhamu

10 years ago

mine also is 50

Davidraph08

1 year ago

why is there -10 in the calculation

Collinsokoruwa

12 years ago

Mine is 50....m(v-u)/t

0.1(15-10)/0.001 =50