The density of water is 1g\(cm^3\) while that of ice is 0.9\(cm^3\), calculate the volume change when 90g of ice is completely melted
a
0\(cm^3\)
b
9\(cm^3\)
c
10\(cm^3\)
d
90\(cm^3\)
e
100\(cm^3\)
Explanation
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Ifeoduyiga
1 year ago
the density of ice 0.9gcm^3 .in solving it, density=mass/volume.
To get ice volume,first what is given,D= 0.9gcm^-3 ,m=90g.insert your values
0.9=90/V. V =100cm^3.
for water volume
1=90/V. V=90cm^3. The volume change=100-90=10cm^3.
That is the answer for the question.


