The density of a body is \(5\times10^3kgm{^-3}\) and it weighs 1N in air. Calculate the apparent weight of the body when totally immersed in water. (Density of water =\(10^3kgm{-3}, g= 10ms^{-2}

salimsm

3 years ago

Mass of the body
m = w/g = 1/10 = 0.1kg
density = mass / volume
volume = mass/density = 0.1/5x10³ = 2x10^-5m³
Uw = pvg = 10³ x 2x10^-5 x 10 = 0.2N

Uw = Wa - Apparent weight
Apparent Weight = Wa - Uw = 1 - 0.2 = 0.8N

Bukason.

11 years ago

i still need explanation plsssssss....