A particle of charge q and mass m moving with a velocity v enters a uniform magnetic field of strength B in the direction of the field. The force on the particle is
a
qvB
b
mqvB
c
qvB/m
d
mvB/q
Explanation
Correct Option
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Discussions (3)

Sammyking2019
6 years ago
my school, i doubt the answer is correct or maybe the question is wrong...
the questions says the force when it moves in the direction of field...
answer is 0 because no force when in the direction of field i.e parallel
F=qVBsin•
where sin • is=0
thus
F=qVB*0 =F=0
but when force is perpendicular maximum force is obtained.
sin• =90= 1
F=qVB*1
F=qVB
there for the answer to the question above should have being 0



