A 10 Ω coil takes 21 s to melt 10g of ice at 0ºC. Assuming no heat losses, determine the current in the coil. (Specific latent heat of fusion of ice = 336 Jg\(^{-1}\))
Heat lost = Heat used to melt ice
I\(^2\)R t = mL
I\(^2\) x 10 x 21 = 10 x 336
I\(^2\) = \(\frac{3360}{210}\) = 16
I = \(\sqrt{16}\) = 4A.
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