A 10 Ω coil takes 21 s to melt 10g of ice at 0ºC. Assuming no heat losses, determine the current in the coil. (Specific latent heat of fusion of ice = 336 Jg\(^{-1}\))

martin1998

9 years ago

Here is an explanation:

Pt=ml

I^2Rt=ml

I^2 x 21x 10=10x 336

I^2=16

I=4A

Shozlee

12 years ago

Using the Formula



Q=ML ; Q=I^2 * R * t



input the given variables..............



I^2 = 10*336 / 10*21



I^2 = 16



I = square root of 16 = 4A



option C

Kingvon1011

1 year ago

Incomplete question