In a uniform electric field, the magnitude of the force on a charge of 0.2 C is 4N. Calculate the electric field intensity

a

20 N C-1

b

8 N C-1

c

5 N C-1

d

2 N C-1

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victorgra
6 years ago

E=f/q
where f is in newton
q is in coulomb
therefore E=4/0.2= 20 newton per coulomb

armandmyschool
2 years ago

Electric field intensity=Force/Charge
E=4/0.2
E=20N/C

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