The temperature of a piece of metal of mass 9 g is raised from 10^oC to 110^oC when it absorbs 108J of heat energy. Determine the specific heat capacity of the metal in J kg^-1K^-1

Rbics

10 years ago

Here is an explanation:

The formula for SHC is

Q= Mc (change in Temperature)..... Where Q= Quantity of heat required or absorbed... M= mass of substance heated ... C= Specific heat capacity... So back to the Question..

Q= 108j,,,, change in temp. = (110-100) = 100,,,,M= 9g = 0.009Kg .....C= ??...

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Q= MC (change in temp)

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108= 0.009 x C x 100

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C= 108/0.9

C= 120....

Yeap

REF: Check Essential Physics Textbook, Page 178 for reference

theovicg

11 years ago

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Majidadi02

4 years ago

M=9g =0.009kg temp. 1=10°C temp. 2=110°C H=108j c=?
H=mc@
Where @=change in temp.
108=0.009×c×100
108=0.9c
c=108/0.9
c=120jkg-1k-1

mesomatic

1 year ago

Tell me answer