An iron rod of length 50m and at a temperature of 60^oC is heated to 70^oC. Calculate its new length. (Linear expansivity of iron = 1.2 x 10^-5K^-1)

Feistar

2 years ago

L2= length x linear expensivity of iron rod x change in teperature

change in temeprature= 70-60=10
Linear expansivity of iron = 1.2 x 10-5K

L2= 50x 1.2x10(raise to power -5) = 0.006

new length = 50+ 0.006

= 50.006m