A trolley of mass 4kg moving on a smooth horizontal platform with a speed of 1.0ms^-1 collides perfectly with a stationary trolley of the same mass on the same platform. Calculate the total momentum of the two trolleys immediately after the collision.

Destiny346

2 years ago

Good day, this is my first time of posting a contribution. let me go straight to the point.

since we all know that the options are given in the units Ns and from Newton's 2nd law of motion F=m(v-u)/t if you cross multiply you get Ft = m(v-u) and Ft is actually impulse

And we are told that the mass of the body before collision is 4kg and the velocity is 1ms-¹ so after collision they will have a common velocity of 1ms-¹ by calculation because the mass of the second body after collision is equal to the mass lf the first body before collision you can verify by checking the question again.

there
m = 4kg

v = 1ms-¹

there momentum is 4kgs-1

which is also equal to Ft

and the unit of Ft is Ns

there fore 4Ns

i hope you understand my point

Thank you.

aloma2008

2 months ago

it’s literally m(change in v)

Akpotoboredestiny

5 years ago

A trolley of mass 4kg moving on a smooth horizontal platform with a speed of 1.0ms-1 collides perfectly with a stationary trolley of the same mass on the same platform. Calculate the total momentum of the two trolleys immediately after the collision.

Pacifica

3 years ago

The examiners are literally just trying to confuse you with all this comprehensions.


This is actually mass x acceleration.
With the formula, F=ma.