Correct Answer: Option C

Explanation

Initial count rate N\(_o\) = 400 per minute, Half-life\(T_{\frac{1}{2}}\) = 5 days, T = 15days, N (count after 15 days) = ?

Using: N =  N\(_o\)(\(\frac{1}{2}\))\(^{\frac{T}{T_{\frac{1}{2}}}}\)

N = 400 x (\(\frac{1}{2}\))\(^{\frac{15}{5}}\)

N = 400 x \(\frac{1}{2}\)\(^3\) = 400 x \(\frac{1}{8}\) = \(\frac{400}{8}\) = 50.

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