Calculate the amount of heat generated in an external load of resistance 8Ω if an alternating current of peak value 5A is passed through for 100s.
E = I\(_{rms}\)\(^2\)Rt
I\(_{rms}\) = \(\frac{I_o}{\sqrt{2}}\) = \(\frac{5}{\sqrt{2}}\) = 3.5355
E = 12.5 x 8 x 100 = 10,000J
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