A string of length 1.0 m vibrates in 10 loops. If the total mass of the string is 1.0 x 10^-3 kg and the tension in it is 10N, calculate the frequency of the vibration.

samcody

5 years ago

the anwser is A..

f=1/2L root T/M...
f=1/2×1 root 10/1×10*-3
f=50htz

OsagieN

2 years ago

𝐟 = 𝐧/𝟮𝐋 (√(𝐓/μ)

μ = 𝟭𝟬⁻³.........𝐧 = 𝟭𝟬

𝐟 = 𝟱𝟬𝟬 𝗛𝘇.....𝐄

Jade12301

1 year ago

Actually, the correct answer is 500Hz. The question specified clearly that the string vibrated in 10 loops. With that said, after finding your fundamental frequency, which is 50Hz, there is need to multiply by 10, to get the frequency of the VIBRATION

Josephwale

4 years ago

Answer is E

note: it vibrate in 10 loops which is equivalent to 10 X 50 = 500Hz

Nnaaaaa

7 years ago

It 100
Frequency of vibration =√[T/M]
Where T=tension
M=mass=mass per unit length of string
The answer is 100hz