A converging lens of focal length 5cm forms a virtual image which is 10cm from the lens. How far from the lens is the object?
\(f = \frac{uv}{u+v}\)
\(5 = \frac{-10u}{-10+u}\)
\(50 + 5u = -10u\)
\(50 = -10u - 5u\)
\(u = \frac{50}{-15}\)
u= -3.3cm
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}