A 400W immersion heater is used to heat a liquid of mass 0.5kg. lf the temperature of the liquid increases by 2.5^oC in one second, calculate the specific heat capacity of the liquid (Neglect heat losses to the surroundings)

80 Jkg^-1K^-1

320Jkg^-1K^-1

500Jkg^-1K^-1

1200J kg^-1K^-1

2000J kg^-1K^-1.

Correct Option

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4 years ago

pls can someone explain this question.
i dont understand it

4 years ago

12 years ago

it's very simple

11 years ago

Pt=mcΔØ....P=power(400), t=time(1sec), m=mass(0.5kg), c=specific heat capacity(?), ΔØ=change in temperatures(2.5Ø)

ceoofwahala

20th June, 2026

Chemistry

2 comments

ASSAAS

20th June, 2026

English Language

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infinitehoaxx

21st May, 2026

Computer

4 comments

A 400W immersion heater is used to heat a liquid of mass 0.5kg. lf the temperature of the liquid increases by 2.5oC in one second, calculate the specific heat capacity of the liquid (Neglect heat losses to the surroundings)