The pressure of a fixed mass of gas is 2.0 x 105Nm-2 at a known temperature. Assuming that the temperature remains constant, what will be the pressure of the gas if its volume is halved?
1.0x105Nm-2
2.0X105Nm-2
3.0x105Nm-2
4.0 x105Nm-2
5.0 x105Nm-2
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Discussions (11)
Now, time to dance.
Remember p1v1/T1= p2v2/ T2
And p1=2.0×10^5Nm², p2=?, T=constant (273k), v1= standard volume (760MMHg), v2=half of v1 (380MMHg)
Therefore 2.0×10^5×760/273 = p2 ×380/273.
103740p2/103740= 4.1496×10^10/103740.
Therefore p2=400000 or 4.0×10^5Nm².
Myschool the correct answer is option D . Cos if the volume is halfed the pressure will double and vice versa according to boyle's law
Myschool the correct answer is option D . Cos if the volume is halfed the pressure will double according to boyle's law
nna ehh dis myschool u guys are misleading and adding to our frustration...which kind tin b dis na...u advice us to patronize ur web for cbt practise yet u dont evn review d questions or ans u put on ur data base.....
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#plight of a Nigerian prospective undergraduate#
The answer is correct for liquid and not gas. For gas, when the volume is halved, the pressure will increase by two
Even without calculation the answer is D. Pressure is inversely proportional to volume provided temp remains constant. So if the volume is halved, the pressure will increade by 2.
Even without calculation the answer is D. Pressure is inversely proportional to volume provided temp remains constant. So if the volume is halved, the pressure will increase by 2.
