A body of mass 2kg is suspended from the ceiling of a lift with a light inextensible string. lf the lift moves upwards with acceleration of 2ms-2, calculate the magnitude of the tension in the string (g = 1Oms-2)

Primus113

5 years ago

24.

when the lift is moving upward
T = ma+mg

when its moving downward

T= ma-mg

temiuel

10 years ago

The correct ans is '24'

T=m(g+a) upward direction

T=m(g-a) downward direction

Therefore,'T'=2(10+2)

T=24N

JATMAC

5 years ago

the answer is 24
when moving upward it is mg+ma

Repq

4 years ago

MYSCHOOL
This isn't encouraging
You guys choosing the wrong answer and still accompanying it with wrong solutions
The correct formula to use is m(g+a)
Which will give you an answer of 24N
Please correct it!!!!

Bboyz

9 years ago

Temiuel's right

readalot

1 year ago

That isn't the correct answer, because practically when going up in a lift, you begin to feel as if weight is added to your own weight. Therefore the correct formula is : T = m(g+a), T = 2( 10 + 2), T= 2( 12), T=24

Pablo_G1000

1 year ago

T - mg = ma
T = mg + ma
T = m(g+a)
T = 2 (10+2)
T = 2 ×12
T =24

ayovang

9 years ago

are these answers from jamb or what because i don't wanna be misled

Matildachy

9 years ago

they are right using this formula mg-T=ma IE 2*10-T=2*2 which is 20-T=4 making T subject -T=4-20 IE -T=-16 .- cancels - giving you 16