A moving-coil meter with an internal resistance of 100 Ω has a full-scale deflection when a current of 10 mA flows through it. What value of resistance would convert it to read 10 V at full-scale deflection?

engineer joshua

12 years ago

i need an expl

Valentineezekiel

3 years ago

There's a formular to this
which is R=V-Igrg/Ig
where
R=value for resistance
V=Voltage
rg=internal resistance of the galvanometer that gave the full scale deflection
Ig=current of the galvanometer
therefore
R=?
Ig=10mA=10/1000=0.01A
rg=100
V=10V
R=10-100*0.01/0.01
=10-1/0.01
=9/0.01
=900

Mr320

2 years ago

The question is not correct

darkypearl

12 years ago

sm1shud pls xplain aw ds is cal