A radioactive nuclide of mass 6.09 has a half-life of 8 days. Calculate the time during which 5.25g of the nuclide would have decayed

Daniel Brainy

8 years ago

After 8 days, 3.045g decays ,after 18days another 1.5225g decays. Finally, after 24 days, another 0.76125g disintegrates.

These add up to approximately 5.3g

theovicg

11 years ago

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Iyangosteve

4 years ago

Original mass=6.0g
Half life=8
N=Original mass- reminant
N= Noe^-kt
Where No= original mass
6-5.25= 0.75
k=0.693/8= 0.0866
0.75= 6e^-0.0866t
Divide both sides by 6
0.125=e^-0.0866
Find the log of both sides
Log0.125= -0.0866tloge
-0.903= -0.0866t(0.434)
-0.903= -0.038t
Divide both sides by -0.903
t= 24days

Drollazz

11 years ago

how did u get that

darkypearl

12 years ago

AW S DS CAL.PLS

JThomson

6 years ago

T1/2=0.693/k

k=0.693/8

=0.086625

No/N=e^(kt)

Ln(No/N)=kt

t=Ln(No/N)/k


No=6.09g and N=6.09-5.25=0.84g

[Ln(6.09/0.84)]/0.086625=t

t=22.87 days

So approximately 3 half lifes which is=3×8=24 days
Where T1/2 is half life, No is the initial mass, N is the final mass and k is the decay constant.