The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?

LAWAL MARIAM

9 years ago

we should not forget micro farad d it is 10^-6

raymond99

10 years ago

The Answer is correct using

€=½cv^2

40×2=5×10^-5×v^2

V^2=16000000

V=4000v

emskodaddy

11 years ago

B IS D ANS

vickyf

9 years ago

no...very wrong...myschool do d correctoin naw....it is 4v....1/2cv²....

doctormmusa

10 years ago

formula is Q=CV

doctormmusa

10 years ago

sorry the formula is Q=1/2(CV)

where q=charge, c=capacitor v =p.d or voltage

GreatEgnrOpemipo

9 months ago

the answer is b

mllebeate

11 years ago

PLS,What's the formula??

Sensei

2 months ago

As how na

olaleyeh

8 years ago

the answer is b

Stellamarisogbunachi

11 years ago

The answer is incorrect cos the formulae to use is 1/2CV2.after solving i got 4V.

ejinwaconfidence@gmail.com

10 years ago

Myschool.com the answer is 4V...half C V-square for energy stored in a capacitor...pls make corrections

olaleyeh

8 years ago

the answer is 4v. according to the formula.
change it or you will be sued for wrong information. for your information my dad is a judge. try yourselves first and see.