A charge of 1.6 x 10^-10C is placed in a uniform electric field of intensity 2.0 x 10⁵NC^-1. What is the magnitude of the electric force exerted on the charge?

3.2 x10⁵N

1.8 x10⁵N

3.2 x10^-5N

1.8 x10^-5N

4.0X10^-6N

Correct Option

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11 years ago

Electric field intesity=

Force/Charge(NC-1) ie E=F/q= where F=Eq

F=(2.0X10^5)(1.6x10^-10)

F=(3.2X10^5-10)

F=3.2x10^-5N

ceoofwahala

20th June, 2026

Chemistry

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ASSAAS

20th June, 2026

English Language

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infinitehoaxx

21st May, 2026

Computer

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A charge of 1.6 x 10-10C is placed in a uniform electric field of intensity 2.0 x 105NC-1. What is the magnitude of the electric force exerted on the charge?