An air bubble of volume 2 cm\(^3\) is formed 20m under water. What will be its volume when it rises to just below the surface of the water if the atmospheric pressure is equivalent to a height of 10m of water?

Okessmyname

12 years ago

the correct answer is 6cm3 cause pressure increase with depth and P1=20+10=30 while P2=10 and V1=2cm3 and V2=? Using boyle's law V2=P1*V1/P2......V2=30*2/10=6cm3

Mayorlizz

1 year ago

P1=p+H
p1=10+20=30
V1=2
P2=10
V2=?
P1V1=P2V2
30*2=10V2
V2=60/10
V2=6Cm3
A

KillerBobo15

5 years ago

The right answer is A

FavourKings

8 years ago

P1V1=P2V2

2*20=10V2

10V2=40

V2=40/10 =4

.'. B: 4cm3 is correct