Correct Answer: Option C

Explanation

\(\text{Given times: } 44.3 \, \text{s}, \, 45.5 \, \text{s}, \, 45.7 \, \text{s}\)

Sum the total times:
\(\text{Total time} = 44.3 + 45.5 + 45.7 = 135.5 \, \text{s}\)

Calculate the mean time for 20 oscillations:
\(\text{Mean time} = \frac{135.5 \, \text{s}}{3} = 45.17 \, \text{s}\)

Find the mean period of oscillation (for one oscillation):
\(\text{Mean period} = \frac{45.17 \, \text{s}}{20} = 2.2585 \, \text{s}\)

Thus, the mean period of oscillation of the pendulum is approximately  2.26 seconds.

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