The image of a pin formed by a diverging lens of focal length 10cm is 5cm from the lens. Calculate the distance of the pin from the lens

machays

2 years ago

It should be -3.3cm

SureTeeBoy

5 years ago

All answers are wrong. The image distance of an object formed by a diverging lens can never be of higher magnitude than the object distance. A diverging lens never forms an image located behind the object. It is always formed inbetween the object and the lens. Since the image distance here is already 5cm, the 3.3cm as object distace is automatically ruled out already. The only logical answer left is the 10cm.

Doing the calculation, 1/f - 1/v = 1/u.
f= -10, v = -5
-1/10 - (-1/5) = 1/u
-1/10 + 1/5 = 1/u
1/10 = 1/u
u = 10cm

Omo_bo_lan_le

1 year ago

wrong answer

Flyboi

10 years ago

Dam! I made a silly mistake.

darkypearl

12 years ago

where d hel did dey get 3 from?

Evans lds

12 years ago

I fear........o

kanynzube

9 years ago

am doubtful of that answer cos the formula is wrong,1/U -1/V =1/F, the correct lens formula is this 1/U+1/V=1/F.