A body accelerates uniformly from rest at the rate of 3 m/s\(^2\) for 8 seconds. Calculate the distance covered by the body during the acceleration?

Judy08

3 years ago

METHOD 1;
a=3m/s², u=0, t=8s, s=?
v=u+at
v=0+3(8)
v=0+24
v=24
v²=u²+2as
24²=0²+2(3s)
576=0+6s
576=6s
[Divide both sides by 6]
s=96m
METHOD 2;
s=ut+½at²
substitute
s=0×8+½×3×8²
=0+½×3×64
=96m

nwankwodavid

10 years ago

The question is wrongly composed:

the SI unit for acceleration is metre per second square

REF: physics number 45

regony600

9 years ago

We weren't given acceleration.

S=(v+u) /2*t

S=(3+0)/2*8

S=3*4=12m

Bryanudenweze

4 years ago

The SI unit for acceleration isnt m/s it is m/s^2

temiuel

10 years ago

Wrong! The ans is '12' bcos we'll first cal acc we are given vel nt acc.

odionjoshua

8 months ago

show m| the formula