How long will it take to heat 3 kg of water from 28^oC to 88^oC in an electric taking a current of 6 A from an e.m.f. source of 220V?

timiztoons

5 years ago

They supposed to give us specific heat capacity value nah

The_benson

9 years ago

Where did 200 come from?

Leinad321

3 years ago

Workdone=mass×shc×∅
Since m=3kg,shc of water =4200j/kg/k and ∅=88-28=60
W=3×4200×60
W=756000J
Since W=IVT
Making t the subject of formula then
T=W/IVt
T=756000/220×6
T=570s