A work of 30 joules is done is transferring 5 millicoulombs of charge from a point B to a point A in an electric Held. The potential difference between B and A is

dasylva0305

6 years ago

W= QV ; V=W/Q ; W=30J ; Q=5mc= 5 X 10^-3
V= 30/0.005
= 6000V
= 6.0 X 10^3 V

Itzduray

5 years ago

Work done = ½QV
Q= 5 * 10¯³C and W=30J
V= 2W/Q= 2 * 30÷(5 * 10¯³)
V=12000= 1.2 *10⁴V................ (E)

Hannahomotolaakins

3 years ago

W=1/2CV²
V²=2W/1C
V²=2*30/1*5=60/5
=12:V=√12
=3.4*10^-4

prodig_E

2 years ago

W=30 J
Q=5 mC
W = QV
V = 30/5*10^-3
V = 6*10^3

St3ssy

1 year ago

w+#_-

henrytt22

12 years ago

I got it. Why is it marked wrong for me?

theboss01

9 months ago

w = ½QV
30 = ½(5×10^-3)V
60 = 5×10^-3 V
v = 12000
v = 1.2×10⁴ V

KB46

4 years ago

6.0 x103V

DoctorTy

12 years ago

r&i=.30v/5=6.0*10^3