An object R leaves a platform XY with a horizontal velocity of 7m^-1 and lands at Q. lf it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ.(Take g = 1Oms²)

No100

2 years ago

Applying the second equation of motion: S=Ut+½gt²
But since the object leaves in an horizontal direction therefore g=0
Then we have our equation as S=Ut
==>S=7*0.3
=2.10m

peter samson

9 years ago

distance...not velocity

klintweezy

11 years ago

the unit of velocity is not m^-1 buh ms^-1