Physics
WAEC 1990
An object R leaves a platform XY with a horizontal velocity of 7m
-1 and lands at Q. lf it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ.(Take g = 1Oms
2)
-
A.
7.30m
-
B.
2.55m
-
C.
2.10m
-
D.
1.65m
-
E.
0.45m.
Correct Answer: Option C
Explanation
D = v x t = 7 x 0.3 = 2.1m
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