A girl whose mass is 55kg stands on a spring - weighing machine inside a lift. When the lift starts to ascend, its acceleration is 2ms1. What will be the reading on the machine? (Take g = ms^-2)

Miguelbarth

5 years ago

sorry sir but answer is totally wrong...
because the question says what is the mass
in a vacuum space mass does not change it remains constant only weight changes
hence the mass of the body should remain constant.
so the answer is 55kg please correct the answer so people will not make mistake sir thank you

civilianmf

1 year ago

Option A is correct
Because the reading on the machine is the reaction of the floor on the girl since the reaction of the floor on the girl is the apparent weight of the girl
Apparent weight= weight of the girl + the resultant force on the girl
A.W = mg + ma
A W= 55×10 + 55×2
A.W= 660N
Answer Is giving in mass then divide 600 by 10 =660/10 which is equal 66kg
From the answer we can deduce that the girl is pressing downward against the floor on the machine with greater force than when the machine is said to be stationary or moving with uniform uniform velocity since the apparent weight of the girl is less than her true weight