A particle of mass 2.5 x 10^-6kg revolving around the earth has a radial acceleration of 4 X 10⁷ ms^-2. What is the centripetal force of the particles?

Temmy2009

3 years ago

since force=mass×acceleration
F=2.5×10-⁶× 4×10⁷
F=2.5×4×10‐⁶+⁷
F=10×10¹
F=100N

Utonwa1010

1 year ago

The centripetal force
𝐹
acting on a particle moving in a circular path is given by the equation:

𝐹
=
𝑚
𝑎
where:

𝑚
=
2.5
×
10
−
6
kg (mass of the particle),

𝑎
=
4
×
10
7
m/s² (radial acceleration).

Now, plugging in the values:

𝐹
=
(
2.5
×
10
−
6
)
×
(
4
×
10
7
)
𝐹
=
10
2
=
100
N
So, the centripetal force acting on the particle is 100 N. Hope that helps!

Utonwa1010

1 year ago

The centripetal force F acting on a particle moving in a circular path is given by the equation:

𝐹=𝑚𝑎 where:

𝑚=2.5×10−6kg (mass of the particle),

𝑎=4×10m/s² (radial acceleration).

Now, plugging in the values:

𝐹=(2.5×10−6)×(4×107) 𝐹=102=100 N
So, the centripetal force acting on the particle is 100 N. Hope that helps!

Utonwa1010

1 year ago

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