The distance between a node and an anti-node for a transverse wave is equal to

Chrisplendour

2 years ago

its ¥/4
meaning 1/4
same as one quarter.

N-N is ¥/2 ....1/2
A-A is ¥/2.....1/2
A-N is ¥/4....1/4
N-N-N is ¥....1
A-A-A is ¥......1.

lamins

3 years ago

Newschool textbook has a typographical error in its own

montty

10 years ago

The ans is D

Brightonexcellent

1 year ago

In a standing wave, nodes are points of zero displacement, while anti-nodes are points of maximum displacement. The distance between a node and the nearest anti-node is one-quarter (¼) of the wavelength (λ/4).

Thus, the correct answer is: D.


one-quarter of the wavelength

ogunnex

12 years ago

d ansa is d oo

mikesystem

12 years ago

the ans is d

Bookie1888

1 year ago

the answer is C