A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?

Toluwa001

2 years ago

E=v+ir
E=24. r=4
V=?. I=?
Recall,
V=IR
R=32+4=36
V=24
I=R/V=24/36
E=v+ir
24=v+(24/36)4
24=v+2.67
V=24-2.67=21.33

Oreoluwamicheal

3 years ago

please where did the 36 come from

Adecool01

4 weeks ago

mistake my brotassss

Boss4forlife

6 months ago

The explanation is right

Faauz

3 years ago

please where did 36 came from

Rachyxx2

1 year ago

The explanation is not right

Toluwa001

2 years ago

Same here