A transparent rectangular block 5.0cm thick is placed on a black dot. The dot when viewed from above is seem 3.0cm from the top of the block calculate the refractive index of the material of the block.

Doctordanny

4 years ago

n=real depth/apparent depth
real depth = 5
apparent depth = 3
Therefore, n=5/3.

Evans lds

12 years ago

I fear.......o

machays

2 years ago

It should be 5/3

TennyB

2 years ago

8

Overwatch886

2 years ago

It is meant to be
Refractive index= real depth ÷ apparent depth
That is 5/3

Toluwa001

2 years ago

Wrong answer

GraceTutor

3 years ago

A transparent rectangular block 5.0cm thick is placed on a black dot. The dot when viewed from above is seem 3.0cm from the top of the block calculate the refractive index of the material of the block.

GraceTutor

3 years ago

refractive index= thickness/thickness-displacement
refractive index=5/5-3
5/2

Chimemeria

9 years ago

it's 3/5 not 5/3 pls