0.5kg of water at 10oC is completely converted to ice by extracting 188000J of heat from it. If the specific heat capacity of water is 4200J kg-1C-1, calculate the specific latent heat of fusion of ice.
a
9.0 KJ kg-1
b
84.0 KJ kg-1
c
168.0 KJ kg-1
d
334.0 KJ kg-1
e
336.0 KJ kg-1
Explanation
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Anonymous1468666
3 years ago
using the formula:
Q=mc(change in tempreture)+ mlf
188000=(0.5*4200*10)+0.5lf
188000=21000+0.5lf
188000-21000=0.5lf
167000=0.5lf
lf=167000/0.5
lf=334000J/kg or 334kJ/kg

