0.5kg of water at 10oC is completely converted to ice by extracting 188000J of heat from it. If the specific heat capacity of water is 4200J kg-1C-1, calculate the specific latent heat of fusion of ice.

a

9.0 KJ kg-1

b

84.0 KJ kg-1

c

168.0 KJ kg-1

d

334.0 KJ kg-1

e

336.0 KJ kg-1

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Correct Option
d

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Anonymous1468666
3 years ago

using the formula:
Q=mc(change in tempreture)+ mlf
188000=(0.5*4200*10)+0.5lf
188000=21000+0.5lf
188000-21000=0.5lf
167000=0.5lf
lf=167000/0.5
lf=334000J/kg or 334kJ/kg

Starboy2025
6 months ago

hi

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