The pressure of a given mass of a gas changes from 300Nm\(^{-2}\) to 120Nm\(^{-2}\) while the temperature drops from 127°C to -73°C. The ratio of the final volume to the initial volume is

darkypearl

11 years ago

ans is meant to b 4:5

V1=300*200

V2=120*400



48000/60000

ans is 0.8 whch is 4:5

Hauwababy16

4 years ago

P1V1=P2V2
P1=300, P2=120 ,V1=? ,V2=? ,T1=127°C=127+273=400K
T2=-73°C=-73+273=200K
P1V1/T1=P2V2/T2
300×V1/400=120×V2/200
60000V1=48000V2
V2:V1=60000/48000
=5:4
That's where u guys get it wrong.Assuming they said V1 ratio V2 the answer would have been 4:5

Eyitayo090

5 years ago

The P¹ in the question is 200 and in the solution the p¹ is 300

fabamz01

3 months ago

Alrii, they are correct
I just did my workings again

bimee

12 years ago

yep am in support u guys made a mistake 200 not 3oo

Abimbolaabigeal2026

1 day ago

bcuz according to my workings the final is 4 and initial is 5 therefore the answer is 4:5

King33Victor

1 week ago

solution
data given:
P1 = 300
P2 = 120
T1 = 127+273 = 400k
T2 = -73+273 = 200k

recall:
P1V1/T1 = P2V2/T2
cross and multiply ✖️
P1V1T2 = P2V2T1
300xV1x200 = 120xV2x200
60000V1 = 48000V2
ratio of V2:V1
V2/V1 = 48000/60000
V2/V1 = 5/4
V2/V2 = 5:4

Succe_Lee

1 year ago

I calculated it buh it's wrong

awolusi_ay

5 months ago

thank u

darkypearl

12 years ago

the initial pressure givn was 200 not300.whch makes d answer wrng

Batman55

12 years ago

D answer is 5/6 nt 5/4 pls check it...