A ball is thrown vertically upwards from the ground with an initial velocity of 50ms^-1. What is the total time spent by the ball in the air? (g = 10ms^-2)

Temgd

3 years ago

U= 59 m/s g= 10(always constant) V=O(cuz the ball is thrown upward from the ground) T= ?
V= u-gt
0=50-10×t, = 50-10t
10t/10t = 50/10, t = 5
Time taken to go upward is same as time taken to come down
5+5= 10

Redgiant

6 years ago

Is that really right

Avril

10 years ago

according to projectiles time taken is 2u sin °/g...

so den it will b 2u/g....

dahz anoda way of solving it....

COACHEAA

3 months ago

why should 50-10 be divide

COACHEAA

3 months ago

50-10 is 40 but how they got 5t

Rejoice039

1 year ago

50 subtracted from 10t is equal to 40

odewenusofiyyah

2 years ago

Hg

sunusisani

2 years ago

thanks

anunukem01

12 years ago

pls i dnt undastnd dis at all...hw did u come abt ur 2t?

Dee Keyz❤️❤️

2 months ago

I really don't understand the part of 50 - 10 I thought it is 40 and àw is it 10

scoded

11 years ago

Same here oooo

feranmiadam

3 years ago

Avril juss dey perform magic anyhow