A cell of internal resistance 1Ω supplies current to an external resistor of 3Ω. The efficiency of the cell is

UgwuVictorOsitadinma

8 years ago

Or it could be understood these way too...Eff=R×100/R+r....where R=External resistance,r=internal resistance..

TunmiseOpe

5 years ago

Or E=R/R+r ×100

godspoweraganmwonyi_01

10 months ago

my school it is
r/R *100
so
1/3*100
0.33*100
=33.3%~ approximately 33%
B