A length of wire has a frequency of 225Hz when stretched by a force of 225N. If the force increased to 324N, what is the new frequency of vibration?

Anela

1 year ago

F1/√T1 = F2/√T2
F1=225
T1= 225,
F2=?
T2=324

225/√225 = F2/√324

225/15 = F2/18
CROSS MULTIPLY ✖️

225×18 = 15F2

4050/15 = 270(ANS)

Josephwale

4 years ago

I can only see the right answer and a concurrent solution which are all align to 270Hz... So, everything is cool

Anosike123

2 years ago

As jamb calculator doesn't have √ (square root).
how are we going to solve it

davidshow22

5 years ago

There's an error in the solution please do something about it myschool

krismos

5 years ago

The correct answer is 270Hz, not 306Hz.
225 x 18 / 15 =270Hz and the answer is not in the options given.

Ozny

4 years ago

pls who knows what topic is this question is under
because i dont seem to understand what My school is solving