The pressure of two moles of an ideal gas at a temperature of 27 °C and volume 10\(^-2\)m\(^3\) is?
[R = 8.313 J mol\(^{-1}\)K\(^{-1}\)]
PV = nRT
∴ P = \(\frac{\text{nRT}}{\text{V}}\)
P = \(\frac{2 \times 8.313 \times 300}{10^{-2}}\)
= 4.987 x 10\(^5\) Nm\(^{-2}\)
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