\(^{14}_7\)N + \(^4_2\)He  → \(^{17}_8\)O + X In the equation above, the particles X is?

\(^{14}_7\)N + \(^4_2\)He → \(^{17}_8\)O + X In the equation above, the particles X is?

Physics

JAMB 2008

\(^{14}_7\)N + \(^4_2\)He → \(^{17}_8\)O + X

In the equation above, the particles X is?

A. a proton
B. a neutron
C. an α - particle
D. a β - particle

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Correct Answer: Option A

Explanation

for the conversion of mass 14 + 4 = 17 + x
∴ X = 18 - 17 = 1
for conservation pf charge:7 + 2 = 8 + y
y = 9 - 8 = 1
Thus, the element is 11X which is equal to hydrogen nucleus ( proton)

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\(^{14}_7\)N + \(^4_2\)He → \(^{17}_8\)O + X In the equation above, the particles X is?

Correct Answer: Option A

Explanation

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