The efficiency of the pulley system shown above is 80%. find the effort E required to lift the load of 1200N

Odemosad

1 year ago

VR = numbers of pulley = 4
Ef = MA /VR * 100
MA = 3.2

MA = 1200 / E
E = 1200 / 3.2 = 375N

martinsjesse

8 years ago

`VR=the NO of pulley which is in the diagram and it is 4,when efficiency=MA/VR,so 80/100=MA/4 cross multiply so that we have 100MA=80*4=320/100=3.2, so that is our MA.then when MA=L/E,so that we have 3.2=1200/E then cross multiply so we have 1200/3.2=375.

Wisdomjjj

2 years ago

80/100*4 not 80/10*4

emmytoonz40

5 months ago

correct