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A force F required to keep a 5 kg mass moving round a cycle of...

Physics
JAMB 2008

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

  • A. 4.0 ms-1
  • B. 6.6 ms-1
  • C. 12.1 ms-1
  • D. 21.0 ms-1
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Correct Answer: Option C
Explanation

The force which is centripetal
F = \(\frac{MV^2}{R}\)
= \(\frac{5 \times 7^2}{3.5}\)
= 70

Since force is 70 N when speed is 7m/s

Speed = ? when force 70N is tripled →  70 * 3 = 210N

210 = \(\frac{5×v^2}{3.5}\)
210 × 3.5 = 5 * v\(^2\)
735 ÷ 5 = v\(^2\)
v\(^2\) = 147
v =12.12m/s

There is an explanation video available below.


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Explanation Video

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