The resultant of two forces 12N and 5N is 13N. What is the angle between the two forces?

Zareth

5 months ago

okay so
R=√A²+B²+2ABCos@
13=√12²+5²+2×12×5cos@
13=√144+25+120cos@
Square both sides and simplify
169=169+120cos@
0=120cos@
divide both sides by 120
Cos @ =0
but what's the @
I.e Cos‐¹ 0 = 90
final answer =90
I.e Cos (90)= 0

okiks1999

5 years ago

The diagram for the solution is wrong

Iyegbekedo

2 years ago

please guys what is the cut off mark for uniben nursing 2024

1958hassan

2 months ago

even without disturbing yourself, if you notice, the resultant force is opposite the angle of a right angle triangle which is 90°

divineosnachi

1 year ago

I don't understand

BlessingLB

1 year ago

I don't understand ooo

oblivion999

3 years ago

I don't understand.
Was they using phythogaris theory?

Janeychisom25

2 months ago

pls how did you do the cosine part

Beautifulqueen

1 year ago

i don't really understand

Bamidelezaynab099

1 year ago

Pls but 122+54=176

Alefiajosiah

1 year ago

I don't even need to solve this
just represents the parameters by the right angle triangle

DammyBabs08

1 year ago

I don't understand

tenderm

7 years ago

please what is the cut off mark for nursing, Uniben and unical for this year 2019 jamb