During the nuclear reaction described by
\(^{235}_{92}\)W → \(^{235}_{93}\)X → \(^{231}_{91}\)Y
The particles emitted are respectively
The decay process illustrated above shows that the lost β -particle to decay to the X by increase its atomic number ( from 92 to 93) and leaving the mass no. unaffected. There after, x decayed by -α emission to give Y, by decreasing the mass no. by 2 ( from 93 to 91).
Thus , the emission is β and α particles respectively
There is an explanation video available below.
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